Find x.
(2/(x-2))=(3/(x+5))+(10/(x+5)(x-2))
Multiply both sides of the equation by the LCD to clear the rational expressions. Then you will have a simple linear equation to solve. Check for extraneous solutions.
I don't know what to do for the 3/(x+5) though
Do you know what the LCD is?
(x-2)(x+5)?
Right - now when you multiply on both sides of the equation by that (don't forget to distribute on the RHS) what do you get?
Can you multiply (x-2)(x+5) to 3/(x+5)
\[\left( x-2 \right)\left( x+5 \right) \frac{ 2 }{ x-2 }=\left[\frac{ 3 }{ x+5 }+\frac{ 10 }{( x-2)(x+5) } \right]\left( x-2 \right)\left( x+5 \right)\]
Yes, and what will happen? The denominator will cancel with the factor (x+5), and you'll have 3(x-2) in the numerator. Does that make sense?
Yes
so now you should have: 2(x+5)=3(x-2)+10 Much easier equation to manage from here. :)
Thank you!
You're very welcome, happy to help. :)
I appreciate you taking your time to go through the steps :) Most people just give me the answers
Haha, I hate it when people do that. It's expedient, but won't help you know how to tackle the same kind of problem next time, now will it?? :)
Yep!
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