Question

A car is traveling in a straight line has a velocity of 4.15m/s at some instant. After 3.91s it's velocity is 13m/s.
What is its average acceleration in this time interval?
Answer in units of m/s^2

Answer 1

The car's initial velocity is less than its final velocity. So we know that it is accelerating.
Now do you know that
a = change in velocity/change in time
So you have change in velocity as = v-u = 13m/s-4.15m/s
And you have the time given as = 3.91s
So find acceleration!! :)
Understood? :)