Question

let f(x)=x-2 and g(x)=x^2-7x-9. find f(g(-1))

Answer 1

are you still looking for the inverse?

Answer 2

wait i put it wrong let me try again

Answer 3

let f(x)=x^2-7x-9. find f(g(-1))

Answer 4

and yea im looking for the same thing i was last time

Answer 5

i don't think so this time
i think this is
\[f(g(-1))\]

Answer 6

but i could be wrong
could you take a screen shot of the problem?

Answer 7

your right thats wat it is and my computer dosnt have screen shot im sorry

Answer 8

if it is \(f(g(-1))\) your first step is to compute \(g(-1)\)
do you know how to do that?

Answer 9

make the -1 dissapear

Answer 10

substitute -1 in g(x)
after you find value of g(x), substitute that value to f(x)

Answer 11

lol yeah, make it go away

Answer 12

i got 21 for my answer

Answer 13

\[ g(x)=x^2-7x-9\]\[ g(\heartsuit)=\heartsuit^2-7\heartsuit-9\]\[ g(-1)=(-1)^2-7(-1)-9\]

Answer 14

so the question is, what is
\[(-1)^2-7\times (-1)-9\]

Answer 15

I want to confirm something. Is g(x)=x^2-7x-9 and f(x)=x^2-7x-9?

Answer 16

@eLg it is \(f(x)=x-2\)

Answer 17

no the first part is right but then after the and its f(g(-1))

Answer 18

3

Answer 19

\[1+7-9=-1\] i think

Answer 20

no thats not an option lol this is hard
the options are
-21
-3
3
21

Answer 21

then
\[f(-1)=-1-2=-3\] for a final answer

Answer 22

I got -3

Answer 23

it looks hard because it takes two steps, not one
first you find \(g(-1)\)
then you find \(f\) of whatever you got for the first answer

Answer 24

thank you!! im not sure who to give the medal too.