Ask your own question, for FREE!
Mathematics 26 Online
OpenStudy (gorica):

Value of a line integral

OpenStudy (anonymous):

\[\int\limits_{a}^{b}c dx\]\[=c(b-a)\]

OpenStudy (gorica):

If\[\vec F(r) d \vec r<0, vec r=\vec r(t) \] for all t, is it \[\int\limits_{C} \vec F(r) d \vec r<0\]?

OpenStudy (gorica):

\[\vec r=\vec r(t)\]

OpenStudy (anonymous):

what's vecr? you mean vector?

OpenStudy (gorica):

yes, I made mistake in typing, I corrected myself below

OpenStudy (anonymous):

actually I'm not really good when it come to vectors, so I don't think I understand he question properly, though assume your question missing one term of the integral. then I'll assume it's some other constant D okay?

OpenStudy (gorica):

I made a huge mistake. \[\vec F_v=-k \dot{\vec r}, \dot{\vec r}=\frac{d \vec r}{dt}\] \[\vec F_v d \vec r<0\] I need to know the value of \[\int\limits_{C} \vec F_v d \vec r\]

OpenStudy (gorica):

k is positive constant

OpenStudy (anonymous):

there's no upper term for the integral?!

OpenStudy (gorica):

It's closed integral on closed curve C

OpenStudy (anonymous):

okay I'm really sorry, either I don't think I understand the question , or the value is clearly 0 since the bounds are similar, I wish I could be more convenient :(

OpenStudy (anonymous):

What's the curve? @gorica

OpenStudy (gorica):

what do you mean what's the curve?

OpenStudy (anonymous):

This is a line integral over the curve \(C\), isn't it? What is \(C\)?

OpenStudy (gorica):

You mean if C is a circle, ellipse,...? I don't really understand your question. If you ask about the shape of C, it's not defined. It's an arbitrary closed curve. The shape doesn't matter.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!