Question

can someone help me?

Answer 1

(1,-1) is a point that solves the system of given linear eq.

Answer 2

(1,-1) is what I got the first time, I just want completely sure

Answer 3

I get the same

Answer 4

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiJ4LTIiLCJjb2xvciI6IiNDNzIwQTAifSx7InR5cGUiOjAsImVxIjoiMS0yeCIsImNvbG9yIjoiIzI0MkFDOSJ9LHsidHlwZSI6MTAwMH1d

Answer 5

what about this one? I got (6,5)

Answer 6

@jdoe0001

Answer 7

looking

Answer 8

\(\begin{matrix}
y = \cfrac{1}{2}x +2\\
y = -x-1\\
\textit{multiplying the top by -1}\\
-y = -\cfrac{1}{2}x -2\\
y = -x-1\\
\hline\\
0=-\cfrac{3}{2}x-3\\
\bf3= -\cfrac{3x}{2} \implies \cfrac{3 \cdot 2}{-3} = x \implies -2 = x
\end{matrix}\)

Answer 9

so h0w would i graph this?

Answer 10

so x = -2, and
y = 1/2(-2)+2 => y = 1
(-2, 1)

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIxLzJ4KzIiLCJjb2xvciI6IiNFMzI0MjQifSx7InR5cGUiOjAsImVxIjoiLXgtMSIsImNvbG9yIjoiIzYzMzFFMCJ9LHsidHlwZSI6MTAwMH1d

Answer 11

what abput this one?

Answer 12

well, do the same, multiply the top by -1 and add

Answer 13

im aving some trouble, can you walk me through it?

Answer 14

\(\Large \begin{matrix}
y & = & x\\
y & = & -x & +6\\
&&&&\textit{times -1 on the top one}\\
-y & = & -x& + 0\\
y & = & -x & +6\\
\hline\\
\square?&&\square?&\square?

\end{matrix}\)

Answer 15

keep in mind that in the elimination method, what matters is that we ELIMINATE one by providing a negative or inverse version atop or bottom, so when added together, they'd give 0

Answer 16

well, it should be -0 atop but anyhow

Answer 17

-y = -x + 6?

Answer 18

hmm wait a second... we do have a -x....

Answer 19

well, anyhow, I didn't need to do the -y, there's a -x at the bottom and that would have worked but that's ok

Answer 20

well, what do you get for -y + y?

Answer 21

-sameness + sameness = ?

Answer 22

+y

Answer 23

ok, let's see it in another way

sameness - sameness =?

Answer 24

4-4=0
2-2= 0
3-3=0
a-a= 0
b-b = 0
-4+4 = 0
-2+2=0

-y+y = 0

Answer 25

\(\Large \begin{matrix}
y & = & x\\
y & = & -x & +6\\
&&&&\textit{times -1 on the top one}\\
-y & = & -x& + 0\\
y & = & -x & +6\\
\hline\\
0&=&\square?&\square?
\end{matrix}\)

Answer 26

that's the idea behind the elimination method, to ELIMINATE one of the variables