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Log question: How do I solve for x? 9^4x+5 = 6^2x+8
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\[9^{4x+5}=6^{2x+8}\]
and then I get (4x+5)log9=(2x+8)log6
but I don't know how to simplify that any further
well distribute and you get 4xlog(9) + 5log(9) = 2xlog(6) + 8 log(6) collect like terms 4xlog(9) - 2xlog(6) = 8log(6) - 5log(9) which is x(4log(9) - 2log(6)) = 8log(6) - 5log(9) hopefully this helps... do you need an exact value or just an answer to 3 or so decimal places
I just need to have x equal a simplified fraction so it would be x= 8log6-5log9/4log9-2log6
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thanks for your help!
thats basically the answer, but it can be simplified by applying log laws for powers and subtraction..
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