Log question: How do I solve for x? 9^4x+5 = 6^2x+8

Question

anonymous · Answer

$$9^{4x+5}=6^{2x+8}$$

anonymous · Answer

and then I get (4x+5)log9=(2x+8)log6

anonymous · Answer

but I don't know how to simplify that any further

campbell_st · Answer

well distribute and you get 

4xlog(9) + 5log(9) = 2xlog(6) + 8 log(6) 

collect like terms 

4xlog(9) - 2xlog(6) = 8log(6) - 5log(9)

which is 

x(4log(9) - 2log(6)) = 8log(6) - 5log(9)

hopefully this helps... do you need an exact value or just an answer to 3 or so decimal places

anonymous · Answer

I just need to have x equal a simplified fraction so it would be x= 8log6-5log9/4log9-2log6

anonymous · Answer

thanks for your help!

campbell_st · Answer

thats basically the answer, but it can be simplified by applying log laws for powers and subtraction..