Question

log[2](b)8=v and log[2](b)5=h log[2](b)√(8/125)

Answer 1

how to write the expression in terms of v and h

Answer 2

you need to use the calculator

Answer 3

i can't i'm trying to express it in terms of v and h

Answer 4

im not sure then sorry

Answer 5

ok thanks

Answer 6

I don't understand your logs the way you wrote them.
Is 2 the base?
Or is the base 2b?
What is that 8 doing there?

Is it a base of 2, with b to the 8th power inside the log?

Answer 7

no b is the base sorry...another website added the 2
it is logb8=v and logb5=h and im trying to find logbsqrt(8/125)

Answer 8

anytime it says(2) it means the next number is a base

Answer 9

oh i see :)

Answer 10

\(\bf log_2b^8=v\\
log_25^b=h\\
log_2\left(b\sqrt{\cfrac{8}{25}}\right) \ \ \ ?\)

Answer 11

shoot I even mixed up numbers, one sec

Answer 12

\(\bf log_2b^8=v\\
log_2b^5=h\\
log_2\left(b\sqrt{\cfrac{8}{25}}\right) \ \ \ ?\)

Answer 13

is that what you meant?

Answer 14

no, the base is a b...forget the 2

Answer 15

hmm, how about you use the whiteboard? :)

Answer 16

i dont know how

Answer 17

i dont even know what that it

Answer 18

or post a screenshot

Answer 19

\[\Large \log_b8=v \qquad \log_b5=h\]And we need to write this in terms of v and h?\[\Large \log_b \sqrt{\frac{8}{125}}\]

Answer 20

yes zepdrix

Answer 21

We'll use properties of exponents and logs to mess with this thing, and get it looking the way we want.\[\Large \log_b \sqrt{\frac{8}{125}} \qquad=\qquad \log_b\frac{\sqrt 8}{\sqrt {125}}\qquad=\qquad \log_b\frac{8^{1/2}}{5^{3/2}}\]Confused by any of that so far?

Answer 22

nope that seems good so far

Answer 23

keep in mind that \(\bf \Large {\log_b8=v \implies b^v = 8\\
\log_b5=h \implies b^h = 5}\)

Answer 24

A property of logs tells us,\[\large \log(\frac{a}{b})=\log(a)-\log(b)\]
So let's apply this to our problem.\[\Large \log_b\frac{8^{1/2}}{5^{3/2}} \qquad=\qquad \log_b8^{1/2}-\log_b5^{3/2}\]

Answer 25

ok

Answer 26

Another important property of logs,\[\Large \log(a^c)=c\cdot \log(a)\]

Let's use this rule to move our fractions in front as coefficients.

Answer 27

\[\Large \frac{1}{2}\log_b8-\frac{3}{2}\log_b5\]Hmm we can probably plug in our v and h from here :)

Answer 28

\[\Large \frac{1}{2}\color{#FF11AA}{\log_b8}-\frac{3}{2}\color{#3366CF}{\log_b5}\]

And let's remember our v and h equations they gave us,\[\Large \color{#FF11AA}{\log_b8=v} \qquad \color{#3366CF}{\log_b5=h}\]

Answer 29

1/2v-3/2h?

Answer 30

Yah that sounds right! :)
Did you get confused by what I did with the 125, turning it into a 5?
That's a bit of a tricky step.

Answer 31

no you didnt thanks so much

Answer 32

the statue of liberty is approximately 305 ft tall. if the angle of elevation of a ship is 28.6 degrees, how far, to the nearest foot is the ship from the statues base
any clue with this one

Answer 33

Mmmm did I draw that angle in the correct location? Sometimes I mess that up. Angle of Elevation.. hmm