Ask your own question, for FREE!
Geometry 23 Online
OpenStudy (anonymous):

There is a test that has 43 questions on it. Each question is worth 6 points. How many questions can I get wrong for 70%?

OpenStudy (e.mccormick):

Well, if you think about it, how you get the percentage is dividing what is right by the number of questions. So if you take 1/100 you get .01, or 1%. If there are only 50 questions and you only get 1 right, that is 1/50=.02 or 2%. If you look at that, it is right/total=% as a decimal. So what you want is: right/43=.7 Now solve for right.

OpenStudy (anonymous):

it would be 31. reason being, I started off with 7/10 and turned it into a decimal: .7 = 70% and then I multiplied the .7 by the 43 and got 30.1 which is roughly a 69%. Divide 31 by the 43 and you'll get 72.blahblah. so to answer your question, it would be 12 questions you could get wrong which would result in a 72%.

OpenStudy (anonymous):

yeah the answere would be thirty one because you have to divide the number with the percentage

OpenStudy (e.mccormick):

@GlendaCarter1998 You multiply the number of questions by the percentage, not divide. And as @r.rhoden918 points out, you can only get 12 wrong. While 30.1 is closer to 30 or 13 wrong, if you got 13 wrong you would be below 70%. Usually these questions are how to get 70% or above! Going below the % line given is bad, so you must always round up. Even if a number 0.000001 larger, it needs to round up when talking about how to keep a percentage of a grade.

OpenStudy (anonymous):

well each question is worth 2.33 points, but why would you want to make a 70?

OpenStudy (e.mccormick):

@Cloudy A lot of times these questions come up when a person is first learning percentages. That means they may not want a 70, but more that they are being told to find what makes a 70.

OpenStudy (anonymous):

ok sorry im new to this

OpenStudy (e.mccormick):

Not a problem! I always assume the best about questions here... though your point is valid: one should always aim to do the best they can, not just enough to get by.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!