Question

Write the equation of the circle centered at (9 , -10 ) that passes through (19,15).

Answer 1

first find the distance between (9 , -10 ) and (19,15).
this will give the radius

Answer 2

equation of the circle centred at (h,k) and radius a unit is given by
(x-h)^2 +(y-k)^2=a^2

Answer 3

thats the part im having issues with... i keep getting 5\[\sqrt{13}\]

Answer 4

for the distance

Answer 5

have u checked ur calculation

Answer 6

ya its not right... but idk what i did wrong

Answer 7

i can show you what i did

Answer 8

distance between (9,-10) and (19,15)
=sqrt ( (19-9)^2 + (15+10)^2 )

Answer 9

ok show

Answer 10

\[d=\sqrt{(19-9)^2+(15+10)^2}\]

Answer 11

\[\sqrt{10^2+25^2}\]

Answer 12

\[\sqrt{100+225}\]

Answer 13

\[\sqrt{325}\]

Answer 14

correct
=sqrt(100+625)
so u get sqrt(725) =(sqrt(5*5*29) = 5*29

Answer 15

25^2=625
but u are writing 325 as 15^2=325

Answer 16

oh wow i messed up 25^2 -_-

Answer 17

thx ur awesome

Answer 18

so its \[5\sqrt{29}\] ?

Answer 19

yup
any yw

Answer 20

1 more question... how do i make it into the radius?