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OpenStudy (anonymous):
What is the Integral for cos3xdx??
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OpenStudy (amistre64):
seperate it into sin and cos parts ...
OpenStudy (amistre64):
im assuming that cos^3 (x) hard to read when people dont make use of grouping symbols
OpenStudy (anonymous):
Sorry, it's cos(3x)dx....
OpenStudy (amistre64):
ah, even simpler then
OpenStudy (amistre64):
we know that this had to come from some version of sin(3x) right?
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OpenStudy (anonymous):
Okay
OpenStudy (amistre64):
lets tack on a constant scalar:\[k~\sin(3x)\]
and take the derivative to compare it against what you have
OpenStudy (amistre64):
what would we get for this derivative?
OpenStudy (anonymous):
What about 3 sin (3x) ?
OpenStudy (amistre64):
hmm, lets try that out:
3 sin(3x) derives to 3*3 cos(3x) = 9 cos(3x)
9 cos(3x) is not equal to cos(3x)
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OpenStudy (anonymous):
Mmmm, then 1/3 sin(3x) I presume?
OpenStudy (amistre64):
if we take the derivative of: k sin(3x) we obtain
k sin(3x) derives to 3k cos(3x)
3k cos(3x) = cos(3x) when 3k = 1
so yeah :)
OpenStudy (anonymous):
Awesome!!! Thanks a lot amistre64!!!
OpenStudy (amistre64):
youre welcome
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