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Mathematics 16 Online
OpenStudy (anonymous):

Look at the figure. What is the length of segment KM? 14.1 inches 17.3 inches 10 inches 20 inches

OpenStudy (anonymous):

@Pynewn can you help

OpenStudy (anonymous):

you can use the sine rule or your the trigonometry knowledge

OpenStudy (anonymous):

opposite/hypotenuse..... then what?

OpenStudy (anonymous):

using sine rule. it says: \[\frac{ A }{ \sin (\theta) }=\frac{ B }{ \sin(\alpha) }\],provided angles and opposite sides

OpenStudy (anonymous):

let B=10,\[\theta=30\]and \[\alpha=90\]

OpenStudy (anonymous):

or you can find the hypo. side\[\sin(30)=\frac{ 10 }{ RM }\], than solve for RM, which is equal to 20in.

OpenStudy (ivettef365):

use sin sin(30) = 10/x find x

OpenStudy (anonymous):

why don't you just use sine, since triangle KMN is a right triangle?

OpenStudy (anonymous):

Hold on yea i was gonna ask the same @Pynewn @Data_LG2

OpenStudy (anonymous):

like @ivettef365 just posted

OpenStudy (anonymous):

anyways it's 20 inches

OpenStudy (ivettef365):

correct

OpenStudy (anonymous):

yeap I was just showing the two ways of finding the ans.

OpenStudy (anonymous):

well either way you explained it help me so thanks @Pynewn

OpenStudy (anonymous):

you are welcome

OpenStudy (anonymous):

\[\text{KM}=10\text{ Csc}[30{}^{\circ}]=20 \]

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