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Write the equation of the quadratic function with roots 6 and 10 and a vertex at (8, 2).
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start with \[y=a(x-6)(x-10)\] then find \(a\) be replacing \(x\) by \(8\) and \(y\) by \(2\)
so 2=a(8-6)(8-10)
yes
and isn't that 2=a(2)(-2)
yes
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so what is \(a\) ?
well 2=a(-4) so a= -1/2?
yes
Oh ok, so how would I rewrite the equation?
\[y=-\frac{1}{2}(x-6)(x-10)\] and then multiply out i would multiply \((x-6)(x-10)\) first, then divide each coefficient by \(-2\)
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Thank you!
yw
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