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Mathematics 20 Online
OpenStudy (anonymous):

Raoul prints a poster using an aspect ratio of

OpenStudy (anonymous):

\[\frac{ 4 }{ 5 }\]

OpenStudy (anonymous):

Which of the following aspect ratios could Raoul also use without distorting the picture?

OpenStudy (anonymous):

\[\frac{ 1 }{ 4 }\]

OpenStudy (anonymous):

\[\frac{ 5 }{ 6 }\]

OpenStudy (anonymous):

\[\frac{ 8 }{ 10 }\]

OpenStudy (anonymous):

or \[\frac{ 8 }{ 9 }\]

OpenStudy (anonymous):

i think the question is asking "what fraction is equivalent to \(\frac{4}{5}\)?"

OpenStudy (anonymous):

idk i just putwhat the question says

OpenStudy (anonymous):

k which fraction is equivalent to \(\frac{4}{5}\) out of your list?

OpenStudy (anonymous):

8/10?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so thats the answer?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thx :)

OpenStudy (anonymous):

Which pair of ratios forms a proportion? \[\frac{ 11 }{ 36 },\frac{ 121 }{ 180 }\]

OpenStudy (anonymous):

\[\frac{ 13 }{ 21 },\frac{ 39 }{ 63 }\]

OpenStudy (anonymous):

\[\frac{ 14 }{ 23 },\frac{ 70 }{ 92 }\]

OpenStudy (anonymous):

or\[\frac{ 20 }{ 51 }, \frac{ 4 }{ 5 }\]

OpenStudy (anonymous):

not the last one for sure

OpenStudy (anonymous):

this is what you do to check the first one with a calculator, \[11\times 180\] and \[36\times 121\] if those numbers are the same,then the fractions are equal if not, they are not

OpenStudy (anonymous):

ok so not the first on not the last one?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

for the second one, compute \[13\times 63\] and \[21\times 39\] and see if they are equal

OpenStudy (anonymous):

yes so it is the second one

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Which ratio forms a proportion with\[\frac{ 4 }{ 5 }\]

OpenStudy (anonymous):

\[\frac{ 2 }{ }\]

OpenStudy (anonymous):

\[\frac{ 4 }{ 10 }\]

OpenStudy (anonymous):

\[\frac{4}{5}=\frac{8}{10}=\frac{12}{15}=\frac{16}{20}=...\]

OpenStudy (anonymous):

multiply the top and bottom by the same number, and you get the same fraction

OpenStudy (anonymous):

Solve the x proportion for \[\frac{ 3 }{ x+2 }=\frac{ 6 }{ x-1 }\]

OpenStudy (anonymous):

x = −5 x = 1 x = 4 x = 5

OpenStudy (anonymous):

cross multiply and solve \[3(x-1)=6(x+2)\]

OpenStudy (anonymous):

uh

OpenStudy (anonymous):

do you have any idea what i mean?

OpenStudy (anonymous):

ys

OpenStudy (anonymous):

ok then the first step is to use the distributive property to remove the parentheses

OpenStudy (anonymous):

how are you supposed to multiply 3 by x-1

OpenStudy (anonymous):

\[a(b-c)=ab-ac\] so \[3(x-1)=3\times x-3\times 1\] more succinctly written as \[3x-3\]

OpenStudy (anonymous):

so the answer?

OpenStudy (anonymous):

do the same thing on the right, with the \(6\) and the \((x+2)\)

OpenStudy (anonymous):

maybe it is better if we try this: you have 4 possible answers replace \(x\) by the answers given and see which one works for example, if \(x=4\) then you get \[\frac{3}{4+2}=\frac{6}{4-1}\] or \[\frac{3}{6}=\frac{6}{3}\] which is definitely false, so it is not \(\)

OpenStudy (anonymous):

try \(x=-1\) and see what you get

OpenStudy (anonymous):

like im not even taking this class i cant have the answer?

OpenStudy (anonymous):

lol yeah i told you how to get it where is says "solution" here www.wolframalpha.com/input/?i=\frac{+3+}{+x%2B2+}%3D\frac{+6+}{+x-1+}

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i= \frac{+3+}{+x%2B2+}%3D\frac{+6+}{+x-1+}

OpenStudy (anonymous):

guess you have to copy and paste

OpenStudy (anonymous):

Solve for x in the proportion \[\frac{ 9 }{ 27x }=\frac{ x }{ x+3 }\]

OpenStudy (anonymous):

here this should work http://www.wolframalpha.com/input/?i=3%2F%28x%2B2%29%3D6%2F%28x-1%29

OpenStudy (anonymous):

if you just want the answer, type it in just as you see it you will get it where it says "solution"

OpenStudy (anonymous):

idk what to type in!

OpenStudy (anonymous):

exactly what you wrote look at my example

OpenStudy (anonymous):

you can even copy and paste what you wrote above

OpenStudy (anonymous):

that wasnt any answer options

OpenStudy (anonymous):

debbie gtfo my question

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