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how to find lim x->0 (cos(1/x))/(1+(1/x))
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-1=<cos(1/x)<=+1 and lim (1/(1+1/x)=0 then 0*any value =0
change variable u = 1/x \[\lim_{u \rightarrow \infty} \frac{\cos u}{1+u}\] \[-1<\cos u<1\] thus \[\lim_{u \rightarrow \infty} \frac{\cos u}{1+u} = \frac{n}{\infty} = 0\]
what does the -1<cosu<1 mean?
@me100mks \(\cos x\) for any real \(x\) always gives a value between \(-1\) and \(1\). it should read \(\forall x\in\mathbb{R},-1\le \cos x\le1\)
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