how would i find the slope that is perpendicular to a line that passes through (2,4) and (8,1)

Question

zzr0ck3r · Answer

what is the slope of the line that goes through (2,4) and (8,1)?

zzr0ck3r · Answer

if we have two points $$(x_0,y_0) \space and \space (x_1,y_1)$$
then the slope is $$slope = \frac{y_1-y_0}{x_1-x_0}$$

zzr0ck3r · Answer

so what is the slope @istinkatmath1 ?

anonymous · Answer

the slope would equal to two

zzr0ck3r · Answer

(2,4) and (8,1)
$$\frac{1-4}{8-2}=?$$

anonymous · Answer

3/-6
then you simplify and you get 2

anonymous · Answer

Two lines are perpendicular if the product of their slopes = -1

anonymous · Answer

So if you know the slope of a given line, the slope of the line perpendicular to it is the negative reciprocal

anonymous · Answer

-3/6 = - 1/2
 So it's negative reciprocal is 2

anonymous · Answer

okay thank you so much!

zzr0ck3r · Answer

$$\frac{-3}{6}=\frac{-1}{2}\ne2$$

anonymous · Answer

Who is saying they are equal? -1/2 and 2 are negative reciprocals.  In other words when you multiply them the product is -1. That will now mean the lines are perpendicular