Dirac, Bra-Ket notation
Form 1.5 is some Bra-Ket definitions
In Leonard Susskind 's QM Lecture 1 at 1:02:52 he introduces vectors spaces http://www.youtube.com/results?search_type=videos&search_query=stanford+theoretical+minimum+susskind&search_sort=video_date_uploaded
@Frostbite
The \(\large \delta_{jk}\) most be the Kronecker delta? in the attachment?
yes
\[\langle i|j\rangle=\delta_{ij}=\begin{cases}1&i=j\\0&i\neq j\end{cases}\]
does that describe the vector space
i think they also some times use \(\delta_{ij}=\delta_i^j\) notation
Alright. Well it sure makes sense, I better watch that video. Thank you.
So let me see if I'm just half or totally lost: If we use normalized wavefunctions as I like to do, and should write it using Dirac notation I get that: \[\Large \int\limits_{}^{} \Psi _{n}^{*} \Psi _{m} d \tau=\langle n |m \rangle\]
yeah i think so
Hmmm what do I do with my lovely operators \(\large \hat{\Omega}\)? I suppose they belong in the middle? \[\Large \int\limits_{}^{}\Psi _{n}^{*} \hat{\Omega} \Psi _{m} d \tau=\langle n|\hat{\Omega}|m \rangle\] It seems a little confusing to me :)
i am not familiar with \(\hat\Omega\)
I just wanted Omega to be any observable and the hat that it is a operator.
for probability to be true, the limits of the integral of the wave function over -∞ to ∞ must =1
the ket is a dual vector psace, isnt it?
if ket corresponds to a state whose function is given by \(\psi\), and bra-B, is representaed by a state state \(\phi\) then the state of the system, such as hudrogen, then the relationship is the scalar product \(\int \phi *\psi d\tau\) . idk that's what i read in my notes. Lol.
I just remember doing bra-ket using linear algebra. matrices, and so forth.
@nincompoop ?
@abb0t if you got any additional material I would be very happy, I'm kinda the one who asked UnkleRhaukus if he had any material on it.
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