Question

Please help..
What are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10

(−4, −2) and (2, 5)

(−2, −4) and (2, 5)

(−2, −4) and (5, 2)

No Real Solutions

Answer 1

@Nurali

Answer 2

@DebbieG Help her ^_^ Uri is proud of you.

Answer 3

What methods have you learned for solving a system? Substitution, elimination?

Answer 4

Elimination I think

Answer 5

And some substitution but I cant remember how to do that method

Answer 6

I would probably opt for substitution here, since you have a quadratic (a parabola) and a linear equation (a line). But either would work. If you solve the 2nd equation for y, then you have two equations that both give y as a function of x, right? E.g., you have

y={some stuff}
and
y={some different stuff}

so since y= both of those things, you can set them equal to each other.

Answer 7

When you do that, you'll have a single, quadratic equation to solve.

Answer 8

..... that makes no sense

Answer 9

What part didn't make sense?

Here are your two equations:
\[y=x^2+12x+30\]\[8x-y=10\]Can you solve the 2nd one for y?

Answer 10

Idk how.. I only know how to solve the ones with Y on the other side of the equal sign

Answer 11

You just need to rearrange

8x-y=10

so that the y is by itself.
Try adding y to both sides:

8x-y+y=10+y
What do you get when you simplify that?

Then subtract 10 from both sides.

Answer 12

IM SO FREAKING LOST

Answer 13

THANKS GUYS. I don't need any more help

Answer 14

@jessssloukaa the idea is not to do the problem FOR her.