Question

f(x) = Square root of quantity x plus seven.; g(x) = 8x - 11

Find f(g(x)).

Answer 1

so you have f(x) = \(\sqrt{x+7}\) and g(x)= 8x-11

Answer 2

Yes.

Answer 3

the only thing you need to do is substitute the x from f(x) for the value of g(x) which is
8x -11

Answer 4

Okay...

Answer 5

I still don't get it...

Answer 6

you have f(x) = \(\sqrt{(8x-11)+7}\) you see how I substitute the x

Answer 7

now that is \(\sqrt{8x-4}\)

Answer 8

Here's an example:
Let's have
\[\Large p(\color{red}x) = 8\color{red}x-4\]
and
\[\Large q(x) = \color{blue}{3x+1}\]

So to get
\[\Large p(q(x))\]You just replace the \(\large \color{red}x\) in \(\large p(\color{red}x)\) with \(\large q(x) \)itself like so:
\[\Large p(q(x))= 8(\color{blue}{3x+1})-4\] and then simplify:
\[\Large p(q(x)) = 24x +4\]

Answer 9

@ivettef365 would the final solution be f(g(x)) = . @terenzreignz Thank You for that example, made things a bit simple.