Question

After working to Simplify x^(3/2)*(x+x^(5/2)-x^2), i got x^(11/2)... can someone check to make sure if this is correct?

Answer 1

those fraction exponents will be change in radical .
like this \[\sqrt[2]{x ^{3}}\]

Answer 2

They're much easier to work with as fractions actually. :o\[\Large x^{3/2}(x+x^{5/2}-x^2)\]Distrubuting the x^3/2 gives us,\[\large x^{(1+3/2)}+x^{(5/2+3/2)}-x^{(2-3/2)}\]badaboom,\[\large x^{5/2}+x^{8/2}-x^{1/2}\]

Answer 3

Ah that last term should be x^(2+3/2), my bad!\[\large x^{(1+3/2)}+x^{(5/2+3/2)}-x^{(2+3/2)}\]

Answer 4

So I guess that last term becomes,\[\Large x^{7/2}\]

Answer 5

ya thats what i got when i was working on it

Answer 6

Hmm how did you end up with x^11/2? D: make a boo boo somewhere?

Answer 7

ya its a mistake...it should be x^(6/2) ===> x^3

Answer 8

Careful! You can't add the terms together like that.
We do NOT have,
\[\Large \frac{5}{2}x+\frac{8}{2}x-\frac{7}{2}x\]Which we would be able to add.
We have different powers of x, which cannot be combined through addition.\[\Large x^{5/2}+x^{8/2}-x^{7/2}\]That would be our final answer.

Answer 9

@azureflame241 You could simplify the middle term to x^4 though if you wanted to. :)