Question

how do you do. (xy^6)^-2

Answer 1

\(\Large a^{-n} = \cfrac{1}{a^n}\)

Answer 2

would i set it up (xy^6)/2 then?

Answer 3

indices of variables inside brackets are multiplied by the indice outside the bracket.
As such this equals (x^(1*-2)) * (y^(6*-2)) = x^-2 * y^-12
Using rule posted above this equals 1/(x^2*y^12)
If using rule posted by jdoe001 above from the start....
1/(x * y^6)^2
= 1 divided by { (x^(1*2)) * (y^(6*2)) ]

Note x = x^1, they are the same thing.

Answer 4

i see thank you