(1+cosx)(1+cosy)(1+cosz)-(1-cosx)(1-cosy)(1-cosz)=k then k= ?
I know it's a pain, but if you (egads) multiply out the LHS, then you'll see that there's a LOT of cancellation.
For example: (1+cosx)(1+cosy)(1+cosz) = (1 + cosx + cosy + cosx cosy)(1 + cosz) = 1 + cosz + cosx + cosx cos z + cosy + cosy cosz + cosx cosy + cosx cosy cosz Do the same with second term; and watch things disappear!
well, (1+cosx)(1+cosy)(1+cosz)-(1-cosx)(1-cosy)(1-cosz) = (1+ cosy + cosx + cosx cosy) (1+cosz) - [ (1- cosy - cosx + cosx cosy) (1-cosz)] = (1+cosy+cosx+cosx cosy+cosz+cosycosz+cosxcosz+cosxcosycosz) - [1-cosy-cosx+cosxcosy-cosz+cosycosz+cosxcosz-cosxcosycosz] = 2cosy+2cosx+2cosz+2cosxcosycosz factoring out 2: = 2 (cosy+cosx+cosz+cosxcosycosz) therefore: k = 2 (cosy+cosx+cosz+cosxcosycosz)
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