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Mathematics 14 Online
OpenStudy (b2st):

Check my answer if it's correct? If (2^3)^2 = 4^p, then 3^p = ? .. My answer is 3.. This is how I did it.. If (2^3)^2 = 4^p 2^5 = 2^2p I figure that p = 1, since I have to multiple, and in order to get 4 is 2^2. Then I substitute p=1 to 3^p, and I got the answer 3.

OpenStudy (anonymous):

i think p=3

OpenStudy (b2st):

^ how did you get that??

OpenStudy (anonymous):

\[(2^{2})^{3}=3^{p}\]

OpenStudy (b2st):

I need step please. lol

OpenStudy (anonymous):

\[2^{2}=4 --->4^{3}=4 ^{p}----->p=3\]

OpenStudy (anonymous):

\[(a ^{b})^{c}=(a ^{c})^{b}\]

OpenStudy (b2st):

Uhhh you forgot \[(2^{3})^{2}\]

OpenStudy (psymon):

He's correct about p being 3, though :P

OpenStudy (b2st):

; A; lol i dont get it. plus you're jumping so many steps.

OpenStudy (anonymous):

u can change the place of 2 and 3 in power position

OpenStudy (anonymous):

ok,let me write it again

OpenStudy (b2st):

Can you do the steps from beginning and go each step by step?

OpenStudy (b2st):

I really need a clear understanding, because when you just jump places, I get totally lost. I don't understand what's going on, because I don't know the information about the problem. lol plus this is from a SAT book.

OpenStudy (anonymous):

\[(a ^{b})^{c} = (a ^{c})^{b}\] now tell me,is this right? \[(2^{3})^{2}=(2^{2})^{3}\]

OpenStudy (b2st):

Yes.

OpenStudy (anonymous):

ok,\[2^{2}=?\]

OpenStudy (b2st):

4

OpenStudy (anonymous):

good

OpenStudy (anonymous):

so we have \[4^{3}\],this is the left term,ok?

OpenStudy (anonymous):

the left term is equal to the right term

OpenStudy (b2st):

oh never mind I see it now. Thank you! :D

OpenStudy (anonymous):

ur welcome

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