Okay so word problems make me very nervous and I tend to over-think them ALWAYS. Parking in a student lot costs $1 for the first half hr, and $1.25 for each hr thereafter. A partial hr is charged the same as a full hr. If the student has $10, how long can he park in the lot?
This sounds like a problem Ive seen on mymathlab where the instructions made no sense, lol.
I would interpret it that the first hour charges you a dollar. Then the timer resets and you won't get charged again for another full hour (or a total of an hour and a half elapsed time). So 3o mins in you're down to 9 dollars. So you divided the remaining 9 hours to get 7.2 hours. Well, you're not allowed to do .2 hours, 7.2 is the same as 8 in this problem. So the maximum you can stay on that remaining 9 dollars is 7 hours. Then tack on the initial 30 mins and that would be 7.5 hours. But I remember a problem just like this before and neither me nor the person I was working with interpreted it correctly, lol.
Yeah, that is 7.5
Let's try to prove it mathematically: Subtract the payment from 1st (1/2)hr. That is, 10-1 = 9 Then, let's compute for the next hours possible: 1.25h = 9 h = 7.2 But it was stated that partial hour is charged same as the full hour so disregard .2 Therefore, total hrs = 7+0.5 That is, 7.5 hrs
Actually it must be 7(1.25) +1 well anyway it doesn't reach 10$. It doesn't matter whether the total amount didn't reached 10$ because it is stated that for any partial hr, the cost will be 1.25$ as well. That's why the excess 0.2 hrs in our solution was disregarded.
You better get the LCD first and convert all those fractional coefficient into whole number.
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