Question

Graph the equations using the x and y intercepts. (x/4)-(y/5)=1 I am stuck on this and I cannot figure out how to get this into the right equation/form to be able to graph it.

Answer 1

You may start with finding the x and y intercepts first.
To find the x-intercept, you simply put y=0 into the given equation and solve x. The x value you find is the x-intercept.
Similarly, you can find the y-intercept by putting x=0 into the given equation and solve y. The y value you find is the y-intercept.

After that, you can draw a coordinate plane. Mark the two intercepts you've found and join the two points with a line. That would be the graph for the equation. You are also reminded to draw the equation next to the line you've drawn.

Answer 2

so I would do this:
(x/4)-(0/5)=1
when I subtract the two and find a common denominator I get (5x/20)
this is where I am confused with the fractions I do not know what to do next. If it were not a fraction to begin with I would be ok.

Answer 3

Alright. We'll go through it together.

We're looking for the x-intercept, so we put y=0 into the give equation.
(x/4)-(0/5)=1.

Now, what is 0/5?

Answer 4

It is 0. I have an ordered pair of (8,5) so far.

Answer 5

It is 0, yes. How did you get the ordered pair (8,5)?

Answer 6

if x=8, and y=5
(8/4)-(5/5)=1
2 - 1 =1
also if you do it the long way and find common denominator it will still work out the same. Also (0,5) works. I believe this to be a straight line on the graph

Answer 7

Never mind the second part about (0,5) and the straight line, not sure what I was thinking there,

Answer 8

Here's one (4,0)

Answer 9

(0,5) works because it's a point on the line. If you substitute two numbers (x,y) into the equation ad you've got both sides equal, then it's a point on the line.

Answer 10

(4,0) is right. How did you get that?

Answer 11

I basically used the same concept and I just started plugging in numbers for x and y that would fit into the equation

Answer 12

But, if (4,0) is right (0,5) cannot be

Answer 13

Why can't (0,5) be right?

Answer 14

My first point is (8,5) if I also have a point (4,0) then I cannot have one that is (0,5), however (0,-5) fits into the equation and on the line

Answer 15

Oh! I read something wrong.

Let's see...
For the point (0,5)
Left side = 0/4 - (5/5) = -1
Right side = 1 \(\ne\) left side
So, (0,5) is not a point on the line.

For the point (0,-5)
Left side = 0/4 - (-5)/5 = 1
Right side = 1 = left side.
So, (0,-5) is a point on the line.

Answer 16

Awesome I got it!!! Thank you for working with me on this!!!

Answer 17

You're welcome. But do you know what the x-intercept and y-intercept are?

Answer 18

(4,-6)

Answer 19

Sorry it took me so long, I am at work and I had to do a safety check.

Answer 20

No....

Answer 21

Yes that is the line I got also