Question

Which of the following number combinations is not allowed in an atom?

A) n=2, L=1, m=0
B) n=1, L=0, m=0
C) n=4, L=3, m=-3
D) n=2, L=3, m=2

Answer 1

There are 4 quantum numbers
-the principal quantum number (n) = integer in range 1 to infinity
-the angular quantum number (l) = integer in the range 0 to n-1
-the magnetic quantum number (m) = Ranges from -l to +l
-and the spin quantum number (s) = either -1/2 or +1/2

So n is good in all those options.
Now look at L (the angular quantum number), it's 0 to n-1.
For example in A, n=2 so L = 0 to 2-1 = 0 and 1.
So L is also right.
now m (-l to +l) which is in this case -1, 0 or +1.
So the combination in A is allowed

Answer 2

for B, n=1, L=0 to 1-1 = 0 only.
M= -0 to +0 which just stays 0
So B is also allowed

Answer 3

Can you do the same for C?

Answer 4

Hold on.

Answer 5

Im not 100% sure but no?

Answer 6

n = 4
l = 0 to 4-1 = 0 to 3 = 0, 1, 2 and 3 So n and L are right
Now m?

Answer 7

Where did the 0,1,2 come from? Thats where im partly confused.

Answer 8

it's a range.
when the range is 1 to 4, the numbers in this range are 1, 2 3 and 4 :)

Answer 9

m is the range of -l to +l. So we take the biggest number of L to get the range.
the biggerst number is 3 so the range is -3 to +3
the numbers are -3, -2, -1, 0, 1, 2 and 3.

So C is also allowed :)

Answer 10

Can you check if D is really the answer?

Answer 11

Yes Ill let you know in like 20 minutes

Answer 12

alright

Answer 13

thank you for all your help :)

Answer 14

No problem \(\huge\ddot\smile\)