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if log 2 base x log 2 base 2x=log 2 base 4x then a.x=2^-√2 b.x=2^√2 c.x=1/4 d.x=2^2
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woW !
so confusing, can;t you use the equation mode ? Do you mean :\[\log _{ x}2.\log _{ 2x}2 = \log _{ 4x}2\]
ryt....
solve the equation (1/u)+(1/u+1)=(1/u+2)
did you get sami?
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Do you know the formula : \[\log _{b}a = \frac{ \log _{n} a }{ \log _{n} b }\]
yaa
use the property of logarithms log\[\log_a{b} =1/(\log_b{a}) \]
if yes then 1. apply the formula both sides, 2. take log 2 = a, cause, its a constant anyway, & log x = y 3. simplify to get an algebraic equation in y 4. find y, then x
ans is both A and B
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how r u getting it
i described the solution above
what is u here
a variable equal to \[\log_2{x} \]
okk.i got it
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sure?
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