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Mathematics 13 Online
OpenStudy (amtran_bus):

Annual cost to operate a 100w and 25w light bulb.

OpenStudy (amtran_bus):

OpenStudy (anonymous):

Seems like physics! :/

OpenStudy (e.mccormick):

And what problem are you having with this?

OpenStudy (amtran_bus):

Thankfully not.

OpenStudy (amtran_bus):

I need help with the conversions.

OpenStudy (e.mccormick):

What conversions? They are all in the same units.

OpenStudy (amtran_bus):

This problem

OpenStudy (e.mccormick):

OK... well... kW vs W. k = 1000.

OpenStudy (e.mccormick):

Other than that, I do not see conversions. I just see simple math with variables.

OpenStudy (amtran_bus):

I need help with it all.

OpenStudy (e.mccormick):

OK. So, did you start by getting the numbers and formula out of the question? That is the best thing to do first in any word problem.

OpenStudy (ybarrap):

The units of watts is Joules/sec. We need to see how many Joules (i.e. units of energy) are consumed in one year for 100 Watts and 25 Watts. Start with 100 Watts. Find out how much energy is consumed in one year: 100 Watts = 100 Joules/sec * Number of Seconds in Y year = \(\Large E_{100w}\) We know that charge for energy is $.19/ kw h. Let a=1 kw h = 1000 J/s * 3600 sec So charge per kw h is $0.19/a, which gives units of $ per Joule. Once you get this, multiply times \(\Large E_{100w}\) to get your answer. Repeat for the 25W bulb.

OpenStudy (ybarrap):

Let me know if you have any questions.

OpenStudy (amtran_bus):

Got it right thanks

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