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Find the laplace transform of sin (alpha)t.
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Using the definition of the transform? I would think so, since there's a formula for this on the table.
Integrate by parts. \[\mathcal{L}\left\{\sin \alpha t\right\}=\int_0^\infty \sin\alpha t~e^{-st}~dt\]
I don't want to use the integral to find it. Just looking at the table, what's the answer?
\[\frac{\alpha}{s^2+\alpha^2}\]
Got it, thanks. I was suspicious of the answer.
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