f(x)=3ln(x) Find inverse function & the domain of inverse.
to find inverse: let f(x) = y and invert x and y. so y = 3ln(x) becomes x = 3ln(y). Now solve for y to put it back in the form of a f(x) ln(y) = x/3 inverse operation of ln(y) is e^y e^(ln(y)) = e^(x/3) y = e^(x/3) = g(x) = inverse of f(x)
oh okay thank you!
inverse operation of ln(y) is e^y e^(ln(y)) = e^(x/3)
I ment this step
it is just the definition of the logarithmic function. For: \[y = \log_b(x)\] \[x = b^y\] \[\ln(y) = \log_e(y)\]
Wait but right now my paper says x/3=e^y right
So would it be log e x/3=y
that is the truth. those two equations are equal
oh. i think i see the misunderstanding: the point of that step was that: \[\ln(e^y) = y\]
which is what i meant by inverse operation same way that x = sin^(-1)(y) is the inverse of y = sin(x), used to find the angle x
and that sqrt is inverse of square
So would it be
log e x/2 = y?
yup. assuming that 2 is a typo :)
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