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differention of -r tan nx with respect to x
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Are the r and n values constant? If so, we can pull this r outside and not worry about it too much. It won't affect the differentiation process. \[\Large \left(-r \tan nx\right)' \qquad=\qquad -r\left(\tan nx\right)'\]Do you remember the derivative of tangent? We'll apply the chain rule after you do that step.
why not..?
I'm pretty sure if this was equation was written in terms of polar coordinates it would have been \(\large r\) and \(\large \theta\), not \(\large r\) and \(\large x\). :) But whatever, the original poster seems to be away.. -_-
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