Question

Could somebody remind me how to multiply quaternions

Answer 1

\[q =(\frac{ 1 }{ \sqrt{2} } + \frac{ 1 }{ \sqrt{2} }k)\]
\[r = (i + 2j +3k)\]
i am looking for q*r = ?

Answer 2

0.o

Answer 3

whats wrong pwnzerer :) ?

Answer 4

Well, I could just write out the work, but I think it'll be more useful for you if you did it yourself, and just referred to the multiplication table.

Answer 5

Let me know if you run into any problems, and I'll see what I can do.

Answer 6

i was curious if it was dot or cross :)

Answer 7

\[\sqrt{2}i +3\sqrt{2}j+3\sqrt{2}k-3\sqrt{2}\]
this is what i get, don't think its right

Answer 8

I'm getting something a little bit different. (this can be simplified so that you have \(\sqrt2/2\) isntead of \(1/\sqrt2\)).\[-\frac{i}{\sqrt2}+\frac{3j}{\sqrt2}+\frac{3k}{\sqrt2}-\frac{3}{\sqrt2}\]Are you sure you don't need to be dividing by 2 in your solution? And are you sure about the sign on the \(i\)?

Answer 9

KingGeorge, You have the right answer, its actually the first part of the question as the value that we get after multiplying q and r has to be than multiplied by q^-1 and we should come with -2i+j+3k

Answer 10

Well \(q^{-1}\) should be \[\left(\frac{\sqrt{2}}{2}-\frac{\sqrt2}{2}i\right)\]so one more tedious multiplication, and you should be done.

Answer 11

i cannot imagine anything more fun than quaternion rotation :). Hopefully will not have to do many of them on tomorrows exam. Thank for the help !!!

Answer 12

You're welcome.