Question

cos(theta)tan(theta) + sin ( theta) / tan ( theta) = 2 cos( theta)
should i start out with cos ( theta) sinx/ cosx + sin (theta)

Answer 1

Are you sure you wrote the question properly?
Because cosθ + sinθ is not equal to 2 cosθ! :/

Answer 2

The question stated that cos(θ) tan (θ) + sin ( θ) / tan (θ) = 2 cos ( θ)

Answer 3

For some reason i got 2 sin ( θ)

Answer 4

Question: how about the question? Is it "prove" or "solve"?

Answer 5

I think the question is wee-bit wrong!

Answer 6

It said derive the given identities

Answer 7

\[cos \theta tan\theta + \frac{sin\theta}{tan\theta}= 2 cos\theta ~~~~or~~~\frac{cos\theta tan\theta+sin\theta}{tan\theta} = 2 cos\theta\]

Answer 8

the second one

Answer 9

hehehe... redo please @AkashdeepDeb

Answer 10

hahaha

Answer 11

:P
Forget this the question is worng!
sinθ + cosθ can never in the history of math be 2cosθ
Unless θ = 45'

Answer 12

nope, it's right.!! you see, from the second one, you break it out, you get the first one which you think you are wrong, hahahaha... and it goes to the right handside.

Answer 13

We have to SOLVE this for θ ???
Or PROVE IT????

Answer 14

prove.

Answer 15

ok, let me do

Answer 16

OMG it is the WHOLE goddamn thing divided by tanθ
IS IT??????????

Answer 17

\[\frac{cos \theta tan\theta +sin\theta}{tan\theta} = cos \theta + \frac{sin\theta}{tan\theta}= cos \theta + cos \theta = 2 cos\theta\]hehahahaha

Answer 18

O.O
Use Parenthesis @youndi :D

Answer 19

suggestion: practice Latex

Answer 20

I wil. Thanks alot both of you. I appreciate it :)

Answer 21

:)

Answer 22

yw