solve for x in the following.
7=2-0.5x-0.1x^3

Question

solve for x in the following.
7=2-0.5x-0.1x^3

jdoe0001 · Answer

was that supposed to be $\bf 7=2-0.5x-0.1x^2 \qquad ?$

debbieg · Answer

That would be a lot easier. lol :)

jdoe0001 · Answer

hehe

anonymous · Answer

nope

jdoe0001 · Answer

$\bigodot . \bigodot$

anonymous · Answer

so does no one wan try lol

jdoe0001 · Answer

I have a nagging feeling is $\bf x^2 $

anonymous · Answer

nope its x^3. I'm looking at the paper now

anonymous · Answer

how about this one. graph the piecewise defined function. f(x) is x+3 if x is greater or equal to 0. f(x) is -x+3 if x is less than 0

debbieg · Answer

Well, that's inconvenient.

debbieg · Answer

@jasonfichter if you have a different problem to ask about, please start a separate post. It will be much less confusing. :)

anonymous · Answer

ok

jdoe0001 · Answer

heheh, mind taking a screenshot of the paper?  the equation doesn't seem to fit the context, thus I doubt is $\bf x^3$, unless the procedure is factoring or so

debbieg · Answer

If the equation is as stated, it will make for some ugly solutions. http://www.wolframalpha.com/input/?i=solve+0%3D-5-0.5x-0.1x^3

anonymous · Answer

my teacher said we have to break it into two equations i think. not solve it as one

jdoe0001 · Answer

so, is factoring then

anonymous · Answer

i don't know. ill just skip that one