Suppose that you toss a coin and roll a die. Attached is the sample space is shown in the figure below.What is the probability of obtaining tails or a four? (Enter the probability as a fraction.)
how many ways are there to get tails
6 right
yes, how many ways are there to roll a four
6? so it should be 1/6
6 ways to roll a four?
oh no only 1 way to roll a four
so how many ways total are there to either roll a 4 or get tails?
7?
good, out of how many ways total
7/12 is the probability
totally over thinking that problem
yep, the answer is 7/12
thanks for your help!
you're welcome
can you possibly help with another problem?
sure
The Emory Harrison family of Tennessee had 13 boys. What is the probability of a 13-child family having 13 boys? (Assume that the probability of having a boy or a girl is the same. Round your answer to six decimal places.)
because we have nothing but boys, we would get this (1/2)^n = (1/2)^(13) = (1^13)/(2^13) = 1/8192 again this only works because we're picking the same option each time (in this case, boys)
what is that formula?
the formula is (1/2)^n where n is the number of boys
ok im following
well all I did was plug in n = 13 and simplified to get 1/8192 (it's shown above)
i gotya. its really pretty simple when you break it down. just got to know the formula lol
yes keep in mind that it only works if you have nothing but one gender
right if you had two gender you would do (1/2)^n +(1/2)^g.. where n is equal to number of boys and g is equal to number of girls?
not quite
it's a bit more complicated if you have both genders involved
ok ill leave that alone for now then lol
if you're curious, look up the binomial distribution and you'll find more info about it
absolutely! u must be a teacher lol
kinda, I'm a student learning to become one
i got one last probability problem if your willing to help
sure go for it
well your gonna make a great teacher.
thanks
What is the probability of obtaining exactly four tails in five flips of a coin, given that at least three are tails? (Enter the probability as a fraction.)
the key thing to notice is that it says "given that at least three are tails"
so if we have 5 flips, then the following is possible a) 3 tails, 2 heads b) 4 tails, 1 head c) 5 tails, 0 heads
we have to list out all the possible cases for each scenario
ok im following
i thought the probability would just be 1/2 because it can only be heads or tails
one sec
ok
are you familiar with permutations and combinations?
yes sir
so if ordered mattered, then how many ways are there to arrange 5 items
5! which is 5*4*3*2*1=120
good so if you are arranging TTTHH, then you'll have duplicates to remove the duplicates, you divide by 3!*2! = 6*2 = 12 so 120/12 = 10
this means that there are 10 ways to arrange TTTHH and they are listed below TTTHH TTHTH TTHHT THTTH THTHT THHTT HTTTH HTTHT HTHTT HHTTT
this takes care of scenario a) where we have 3 tails and 2 heads
correct
for scenario b) we have these cases TTTTH TTTHT TTHTT THTTT HTTTT there are 5 cases above and they are easily countable (so no need for a formula here)
and finally in scenario c) we have just this one case: TTTTT
in total, there are 10+5+1 = 16 possible outcomes
so it would be 1/16?
The original question was What is the probability of obtaining exactly four tails in five flips of a coin, given that at least three are tails? (Enter the probability as a fraction.)
there are 16 ways to get at least 3 tails there are 5 ways to get what you want (exactly 4 tails, look at scenario b above) so the probability is 5/16
ahhhhhh. i understand now. you make it seem so simple
that's great, i'm glad you do
thank you for all your help!
you're welcome
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