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Mathematics 25 Online
OpenStudy (anonymous):

Suppose that you toss a coin and roll a die. Attached is the sample space is shown in the figure below.What is the probability of obtaining tails or a four? (Enter the probability as a fraction.)

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

how many ways are there to get tails

OpenStudy (anonymous):

6 right

jimthompson5910 (jim_thompson5910):

yes, how many ways are there to roll a four

OpenStudy (anonymous):

6? so it should be 1/6

jimthompson5910 (jim_thompson5910):

6 ways to roll a four?

OpenStudy (anonymous):

oh no only 1 way to roll a four

jimthompson5910 (jim_thompson5910):

so how many ways total are there to either roll a 4 or get tails?

OpenStudy (anonymous):

7?

jimthompson5910 (jim_thompson5910):

good, out of how many ways total

OpenStudy (anonymous):

7/12 is the probability

OpenStudy (anonymous):

totally over thinking that problem

jimthompson5910 (jim_thompson5910):

yep, the answer is 7/12

OpenStudy (anonymous):

thanks for your help!

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

can you possibly help with another problem?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

The Emory Harrison family of Tennessee had 13 boys. What is the probability of a 13-child family having 13 boys? (Assume that the probability of having a boy or a girl is the same. Round your answer to six decimal places.)

jimthompson5910 (jim_thompson5910):

because we have nothing but boys, we would get this (1/2)^n = (1/2)^(13) = (1^13)/(2^13) = 1/8192 again this only works because we're picking the same option each time (in this case, boys)

OpenStudy (anonymous):

what is that formula?

jimthompson5910 (jim_thompson5910):

the formula is (1/2)^n where n is the number of boys

OpenStudy (anonymous):

ok im following

jimthompson5910 (jim_thompson5910):

well all I did was plug in n = 13 and simplified to get 1/8192 (it's shown above)

OpenStudy (anonymous):

i gotya. its really pretty simple when you break it down. just got to know the formula lol

jimthompson5910 (jim_thompson5910):

yes keep in mind that it only works if you have nothing but one gender

OpenStudy (anonymous):

right if you had two gender you would do (1/2)^n +(1/2)^g.. where n is equal to number of boys and g is equal to number of girls?

jimthompson5910 (jim_thompson5910):

not quite

jimthompson5910 (jim_thompson5910):

it's a bit more complicated if you have both genders involved

OpenStudy (anonymous):

ok ill leave that alone for now then lol

jimthompson5910 (jim_thompson5910):

if you're curious, look up the binomial distribution and you'll find more info about it

OpenStudy (anonymous):

absolutely! u must be a teacher lol

jimthompson5910 (jim_thompson5910):

kinda, I'm a student learning to become one

OpenStudy (anonymous):

i got one last probability problem if your willing to help

jimthompson5910 (jim_thompson5910):

sure go for it

OpenStudy (anonymous):

well your gonna make a great teacher.

jimthompson5910 (jim_thompson5910):

thanks

OpenStudy (anonymous):

What is the probability of obtaining exactly four tails in five flips of a coin, given that at least three are tails? (Enter the probability as a fraction.)

jimthompson5910 (jim_thompson5910):

the key thing to notice is that it says "given that at least three are tails"

jimthompson5910 (jim_thompson5910):

so if we have 5 flips, then the following is possible a) 3 tails, 2 heads b) 4 tails, 1 head c) 5 tails, 0 heads

jimthompson5910 (jim_thompson5910):

we have to list out all the possible cases for each scenario

OpenStudy (anonymous):

ok im following

OpenStudy (anonymous):

i thought the probability would just be 1/2 because it can only be heads or tails

jimthompson5910 (jim_thompson5910):

one sec

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

are you familiar with permutations and combinations?

OpenStudy (anonymous):

yes sir

jimthompson5910 (jim_thompson5910):

so if ordered mattered, then how many ways are there to arrange 5 items

OpenStudy (anonymous):

5! which is 5*4*3*2*1=120

jimthompson5910 (jim_thompson5910):

good so if you are arranging TTTHH, then you'll have duplicates to remove the duplicates, you divide by 3!*2! = 6*2 = 12 so 120/12 = 10

jimthompson5910 (jim_thompson5910):

this means that there are 10 ways to arrange TTTHH and they are listed below TTTHH TTHTH TTHHT THTTH THTHT THHTT HTTTH HTTHT HTHTT HHTTT

jimthompson5910 (jim_thompson5910):

this takes care of scenario a) where we have 3 tails and 2 heads

OpenStudy (anonymous):

correct

jimthompson5910 (jim_thompson5910):

for scenario b) we have these cases TTTTH TTTHT TTHTT THTTT HTTTT there are 5 cases above and they are easily countable (so no need for a formula here)

jimthompson5910 (jim_thompson5910):

and finally in scenario c) we have just this one case: TTTTT

jimthompson5910 (jim_thompson5910):

in total, there are 10+5+1 = 16 possible outcomes

OpenStudy (anonymous):

so it would be 1/16?

jimthompson5910 (jim_thompson5910):

The original question was What is the probability of obtaining exactly four tails in five flips of a coin, given that at least three are tails? (Enter the probability as a fraction.)

jimthompson5910 (jim_thompson5910):

there are 16 ways to get at least 3 tails there are 5 ways to get what you want (exactly 4 tails, look at scenario b above) so the probability is 5/16

OpenStudy (anonymous):

ahhhhhh. i understand now. you make it seem so simple

jimthompson5910 (jim_thompson5910):

that's great, i'm glad you do

OpenStudy (anonymous):

thank you for all your help!

jimthompson5910 (jim_thompson5910):

you're welcome

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