Question

can anyone show me how to get the solution to this radical equation x-3+4=6

Answer 1

\[\sqrt{x-3}+4=6\] maybe?

Answer 2

you wrote
\[x-3+4=6\] which has no radical, so i am guessing

Answer 3

@ satellite73 yes that's exactly it the first way you made it

Answer 4

ok take three steps
1) subtract 4 from both sides
2) square both sides to get rid of the radical on the left
3) add 3 to both sides to get \(x\) by itself

Answer 5

@ satellite73 im still confuse is it 1

Answer 6

\[\sqrt{x-3}+4=6\] subtract 4 from both sides to get
\[\sqrt{x-3}=2\]
then square both sides

Answer 7

you get
\[x-3=7\] now solve for \(x\) by adding 3 to both sides

Answer 8

@ satellite73 i added 3 on both sides i got 6 and 10 what do i do next