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IR + Ir = E solve for I
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\[I(R+r)=E\\I=\frac{E}{R+r}\]
how did you get the I by itself such as in I(R+r)
Okay, see IR and Ir both has an I...
yes
Since they both have one, you can "group like terms" and get I(R+r) To test: |dw:1377465695975:dw| See, we get IR+Ir when we multiply it back, so it is correct
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