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Mathematics 22 Online
OpenStudy (taylormarie213):

IR + Ir = E solve for I

OpenStudy (anonymous):

\[I(R+r)=E\\I=\frac{E}{R+r}\]

OpenStudy (taylormarie213):

how did you get the I by itself such as in I(R+r)

OpenStudy (anonymous):

Okay, see IR and Ir both has an I...

OpenStudy (taylormarie213):

yes

OpenStudy (anonymous):

Since they both have one, you can "group like terms" and get I(R+r) To test: |dw:1377465695975:dw| See, we get IR+Ir when we multiply it back, so it is correct

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