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OpenStudy (raffle_snaffle):
solve for?
OpenStudy (anonymous):
there and back solve for time
OpenStudy (raffle_snaffle):
t=time?
OpenStudy (anonymous):
the whole problem is she went to a place at 80 km/h then returned at 60. the trip back took 4 hours how long did the trip there take?
OpenStudy (raffle_snaffle):
60km/h
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OpenStudy (raffle_snaffle):
okay euler its all you. i can figur this one out though...
OpenStudy (anonymous):
since d there and d back are equal.
r1t1=r2t2
80*4 = 60t2
t = 16/3
OpenStudy (anonymous):
1 and 2 being subscripts for there and back respectively
OpenStudy (anonymous):
um... what is the whole equation im still confused
OpenStudy (anonymous):
d = rt
distance = rate * time
rate is distance/time = speed
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OpenStudy (anonymous):
well yeah but, nevermind
OpenStudy (anonymous):
i'd love to help, but i don't understand the question
OpenStudy (anonymous):
im usually good at math but drts are hard
OpenStudy (anonymous):
\[d=rt\]\[d_{there} = r_{there}*t{there}\]\[d_{back} = r_{back}*t_{back}\]
since the distance there and back is equal:
\[d_{there}=d_{back}\]\[r_{there}*t_{there} = r_{back}*t_{back}\]
plug in values
\[80*4 = 60*t_{back}\]