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Mathematics 23 Online
OpenStudy (anonymous):

d=rt equations

OpenStudy (raffle_snaffle):

solve for?

OpenStudy (anonymous):

there and back solve for time

OpenStudy (raffle_snaffle):

t=time?

OpenStudy (anonymous):

the whole problem is she went to a place at 80 km/h then returned at 60. the trip back took 4 hours how long did the trip there take?

OpenStudy (raffle_snaffle):

60km/h

OpenStudy (raffle_snaffle):

okay euler its all you. i can figur this one out though...

OpenStudy (anonymous):

since d there and d back are equal. r1t1=r2t2 80*4 = 60t2 t = 16/3

OpenStudy (anonymous):

1 and 2 being subscripts for there and back respectively

OpenStudy (anonymous):

um... what is the whole equation im still confused

OpenStudy (anonymous):

d = rt distance = rate * time rate is distance/time = speed

OpenStudy (anonymous):

well yeah but, nevermind

OpenStudy (anonymous):

i'd love to help, but i don't understand the question

OpenStudy (anonymous):

im usually good at math but drts are hard

OpenStudy (anonymous):

\[d=rt\]\[d_{there} = r_{there}*t{there}\]\[d_{back} = r_{back}*t_{back}\] since the distance there and back is equal: \[d_{there}=d_{back}\]\[r_{there}*t_{there} = r_{back}*t_{back}\] plug in values \[80*4 = 60*t_{back}\]

OpenStudy (anonymous):

thanks

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