Mathematics
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OpenStudy (anonymous):
simplify (8x) -2 to the second power
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OpenStudy (luigi0210):
\[a^{-1}=\frac{1}{a}\]
OpenStudy (anonymous):
Im still confused with you answer and my question
OpenStudy (mertsj):
The - part of the exponent means "the reciprocal of"
OpenStudy (mertsj):
So (8x)^-2 means "the reciprocal of 8x" raised to the second power.
OpenStudy (anonymous):
ok so would that mean the answer is 8*8?
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OpenStudy (mertsj):
What is the reciprocal of 8x?
OpenStudy (anonymous):
the problem just asks simplify (8x)^-2
OpenStudy (mertsj):
What is the reciprocal of 8x?
OpenStudy (anonymous):
@Mertsj
OpenStudy (mertsj):
I am aware of what the problem says.
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OpenStudy (anonymous):
ok would it be -64
OpenStudy (mertsj):
What is the reciprocal of 8x?
OpenStudy (anonymous):
1
OpenStudy (mertsj):
So the reason you are having trouble is that you don't know what a reciprocal is?
OpenStudy (anonymous):
correct
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OpenStudy (mertsj):
Let me show you some examples:
OpenStudy (anonymous):
ok great
OpenStudy (mertsj):
|dw:1377485701214:dw|
OpenStudy (mertsj):
So, I ask you for the fourth and final time....what is the reciprocal of 8x ?
OpenStudy (anonymous):
1/8x
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OpenStudy (mertsj):
Now we are making progress.
OpenStudy (mertsj):
\[(8x)^{-2}\]
means take the reciprocal of 8x and square it.
OpenStudy (anonymous):
ok im getting a better understanding now
OpenStudy (mertsj):
So now that we know what the reciprocal is, we have:
\[(8x)^{-2}=(\frac{1}{8x})^2=\frac{1^2}{8^2x^2}=\frac{1}{64x^2}\]
OpenStudy (anonymous):
so instead of being 1/64^-2 it will be 1/64^2
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OpenStudy (mertsj):
It will be:
\[\frac{1}{64x^2}\]
OpenStudy (anonymous):
great thanks
OpenStudy (mertsj):
yw