Question

solve for z

Answer 1

Are you familiar with the pythagorean theorem?

Answer 2

yes ma'am

Answer 3

Is this a trigonometry class?

Answer 4

i think this is solved by ratios but i can never do that so i defer

Answer 5

no
im in the geometry section aarnt i

Answer 6

yes ratios

Answer 7

Side-Splitter Theorem - maybe?

Answer 8

not enough numbers for that

Answer 9

@satellite73 Can you be a bit more specific? I don't know this one.
@GParsley Check out www.purplemath.com - it is a great math resource website.

Answer 10

Give this a try: http://en.wikipedia.org/wiki/Heronian_triangle

Answer 11

can some one else help me??\

Answer 12

@abb0t

Answer 13

@ankit042

Answer 14

Это 45,45,90 треугольника. Используйте этот \[z \sqrt{2}\]

Answer 15

вычислять \[7\sqrt{2}\]

Answer 16

If it were an isosceles triangle, wouldn't the lengths of the hypotenuse be 8 and 8 instead of 9 and 7?

Answer 17

wrong answer bud

Answer 18

I do not understand 'bud'.. Russian has no word for that my friend... Sorry if english is bad..

Answer 19

bud = buddy = pal = friend

to help you with slang terms :) hehe

Answer 20

ok well I really need the answer not learn to how to spaek English...
\

Answer 21

Делай, что я сказал. Использование: \[z \sqrt{2}\]и вычислить его.

Answer 22

not
the
answer

Answer 23

\[\Large z=\sqrt{112}\]Maybe? D:

Answer 24

@J_e_s_u_s You are treating this as an isosceles triangle, it is not.

Answer 25

And parsley go fix your highway problem D:<

Answer 26

Как это нет? Существует углом 90 градусов сверху и одна снизу.Биссектриса делит треугольник на два треугольника.

Answer 27

J_e_s_u_s: From Google Translate: How is it not? There is an angle of 90 degrees above and one below. The bisector divides the triangle into two triangles.

:3

Answer 28

Parsley are you entering these online or something?
Did my answer work? :o

Answer 29

But it does not bisect the angle. If it did, the length of the hypotenuse would be bisected as well.

Answer 30

@zepdrix your answer was not correct

Answer 31

grr :d

Answer 32

want me to tell you the answer choices

Answer 33

yes

Answer 34

да

Answer 35

http://school.pearsoned.com/Pegasus/Modules/AssessmentTool/Presentation/frmStudentPresentation.aspx?&intAssetID=3000000370664190&AssetSubTypeID=0&mode=test&SelectedDay=&from=sp&DRTID=0&CreateModuleID=0&madd=&dsid=&MMNDDal=&ViewID=&AssetLinkID=3000000045440101

Answer 36

We're not logged in +_+ we can't see the choices lol

Answer 37

Нам нужны Вход Для доступа к странице. Просто перечислю ответы.

Answer 38

We cannot log in to that site. Doesn't it give you any hints or some type of instruction?

Answer 39

Просто перечислю ответы.
English

((Just list the answers)

Answer 40

hmmm A) 51
B)12

Answer 41

\[c) 3\sqrt{7}... D) 4\sqrt{7}\]

Answer 42

The hypotenuse (the longest side) is 16, so it has to be one of the options shorter than that :)
Keep that in mind.

Answer 43

Are you sure my answer wasn't right..?

\[\Large \sqrt{112}=4\sqrt7\]

Answer 44

Seems like it might be right D:

Answer 45

How did you get that answer?

Answer 46

It is a right triangle! Angles are 45,45,90!

Answer 47

ik that

Answer 48

thank you @zepdrix

Answer 49

Use formula!
\[x \sqrt{2}\]

Answer 50

@J_e_s_u_s The bottom angles are not 45 and 45. If they were, the hypotenuse of the large triangle would be 8 and 8. It is not.

Answer 51

\[\Large \frac{z}{16}=\frac{7}{z}\]

Answer 52

How does that get you to \(\sqrt{112}\)?

Answer 53

cross multiplying gives us,\[\Large z^2=112\]

Answer 54

16*7=112

Answer 55

Brain dead, sorry. I was canceling instead of cross multiplying. THanks.