Question

x^2 - 5x - 14 = 0
Can someone please explain this. I have to use the quadratic formula.

Answer 1

a=1, b=-5, c=-14

Answer 2

Look up the quadratic formula and replace each a with 1, each b with -5, and each c with -14. Simplify.

Answer 3

\[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

\[ax^2 + bx + c = 0\]

Answer 4

you got this?

Answer 5

course it would be a hell of a lot easier if you wrote
\[(x-7)(x+2)=0\]and solved that one

Answer 6

Unless, of course, the directions say to use the formula.

Answer 7

i think it should say "complete the square"

Answer 8

:/ it doesn't It just said i had to use the quad. formula.

Answer 9

Or "solve by factoring".

Answer 10

That is designed to give you practice with the formula on the simple problems.

Answer 11

\[ax^2+bx+c=0\\x^2-5x-14=0\] so \(a=1, b=-5,c=-14\) substitute in to
\[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] and get
\[\frac{-(-5) \pm \sqrt{(-5)^2-4\times 1\times (-14)}}{2\times 1}\] then do careful arithmetic

Answer 12

thank you i appreciate this

Answer 13

you will know you are right when you get \(-2\) or \(7\)
if you get stuck let us know

Answer 14

Im good from here:-)

Answer 15

k