Question

x^2+3x+8=0 solve

Answer 1

What are we doing? Solving? Factoring? Etc.?

Answer 2

\[x=\frac{ -b+-\sqrt{b^2-4ac} }{ 2a }\]

Answer 3

a=1, b=3 and c=8

Answer 4

You can use the quadratic formula to solve this. This is the quadratic formula:\[ax^2+bx+c=0 \\ x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
So, for your equation:
\[ x=\frac{-3 \pm \sqrt{9-32}}{2} = \frac{-3 \pm i\sqrt{23}}{2}\]

Answer 5

\[x=\frac{ -3+-\sqrt{3^2-4(1)(8)} }{ 2(1) }\]

Answer 6

@Nurali , I think you should write :
\[x _{1} , x _{2} = ...\]
and I think this is incorrect:
\[x = \]
because we don't have a single answer...
but the formula is correct :)