Question

4-(6x^2-2)/(15)=(5x^2)/(3) - (5(x^2-2))/2

Answer 1

\[\large4-\frac{6x^2-2}{15}=\frac{5x^2}{3}-\frac{5(x^2-2)}{2}\]??

Answer 2

Yes.

Answer 3

i can't see any snappy way to do this, you might want to start with
\[\frac{5x^2}{3}-\frac{5(x^2-2)}{2}+\frac{6x^2-2}{15}=4\] then multiply both sides by 30
otherwise you have to add the fractions

Answer 4

yeah, that is probably best
you get
\[10\times 5x^2-15\times 5(x^2-2)+2(6x^2-2)=120\] then clean up the left and solve for \(x\)

Answer 5

Thank you.

Answer 6

it really cleans up a lot
you should end up i think with \[x^2=2\] but check that
yw