What is the equation of a line passing through the point (a,b) and having a slope of b?

Question

amriju · Answer

Take the standard eqn of the line thats y=mx+c..m is slope...so (a,b)  must satisfy the eqn...and mis provided to be b...so b=ab+c...since c is a constant...we have c=b(1-a)...so the eqn is y=bx+b(1-a)..

anonymous · Answer

use the point slope formula 
$$y-y_1=m(x-x_1)$$ with $m=b, x_1=a, y_1=b$

anonymous · Answer

you get 
$$y-b=b(x-a)$$

anonymous · Answer

Wait that's not one of the answers.
I have..
Y= -bx - b (1 - a)
Y= bx - b(a-1)
Y= 1/b x + b(a-1)
Y= -1/box + b(1-a)

anonymous · Answer

so you can see that each of your answers has $y=\text{something}$
your job is to take 
$$y-b=b(x-a)$$ and solve for $y$

amriju · Answer

b dear...b(1-a)=-b(a-1) isn't it??

anonymous · Answer

actually you don't  have to do anything
your are told that the slope is $b$ 
only one of your possible answers has slope $b$

anonymous · Answer

$$y= -bx - b (1 - a)\ y= bx - b(a-1)\ y= 1/b x + b(a-1) \y= -1/bx + b(1-a)$$

amriju · Answer

lololol..:P...cool..

anonymous · Answer

only the second one has slope $b$ so either that is the right choice or none of them are