Ask your own question, for FREE!
Geometry 21 Online
OpenStudy (anonymous):

Questions are attached

OpenStudy (anonymous):

OpenStudy (anonymous):

Here's an idea: ask *how* to do it, not what the answer is.

OpenStudy (anonymous):

I'm not asking for the answer. I would like to know how to solve the problems.

OpenStudy (theeric):

To both of you, I was thinking about the same thing! @Anickyan , to be precise, nothing was asked yet... @Amarie31 , similarly, you did not ask anything. Normally people will see a problem and maybe walk you through it. I think the best way to learn, when there isn't a community to help, is to formulate specific questions, like, "what is the degree of a polynomial?" Or others. Sometimes you have to delve into the problem just to find what to ask, and you learn how to do it in the process! That's great! And for interactive help, OpenStudy is here :) So, where are you having a problem? If you're like I am/was, you'll look at it and say "the whole thing." But now I more usually try to make sure I understand the question thoroughly - every word - before I decide I don't know what to do. Do you have a specific problem, or do you want a hint?

OpenStudy (theeric):

I only have one half hour to help right now!

OpenStudy (anonymous):

I don't understand problem 53

OpenStudy (theeric):

So, maybe I can help you understand everything. Do you know what the degree of a polynomial is?

OpenStudy (anonymous):

No I do not know

OpenStudy (theeric):

Okay! Well, you find the term where the variable(s) have the highest powers combined. I assume you're just using one variable, so the "order" is the same number as the highest power. Well, a polynomial has many terms (added/subtracted pieces) and the varibles have different exponents, like \(2x^2+x+4\). So, the \(2x^2\) has the highest power, \(2\). So the order is \(2\), so second order.

OpenStudy (anonymous):

Alright that makes sense

OpenStudy (theeric):

Now, these polynomials can make funky curves, like |dw:1377538217745:dw|and stuff like that.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!