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OpenStudy (anonymous):
OpenStudy (anonymous):
@KeithAfasCalcLover
OpenStudy (anonymous):
Hey
OpenStudy (anonymous):
Ok one second...
OpenStudy (anonymous):
please hurry
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OpenStudy (anonymous):
Alright. You notice how in the picture, Comparing the most outers quare no the next square inside, they form a triangle?
OpenStudy (anonymous):
ok.. ya
OpenStudy (anonymous):
Lets say that the side of the first square is \(S_1\). And the side of the next inner square is \(S_2\) and so on and so forth?
Then the length of the second square is:
\[S_2=\left(\frac{S_1}{2}\right)^2+\left(\frac{S_1}{2}\right)^2=2\left(\frac{S_1}{2}\right)^2=2\frac{(S_1)^2}{4}=\frac{(S_1)^2}{2}\]
OpenStudy (anonymous):
The same would be for the side of the fifth square:
\[S_5=\left(\frac{S_4}{2}\right)^2+\left(\frac{S_4}{2}\right)^2=2\left(\frac{S_4}{2}\right)^2=2\frac{(S_4)^2}{4}=\frac{(S_4)^2}{2}\]
OpenStudy (anonymous):
what is the answer then?
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OpenStudy (anonymous):
So we can make a chain of equations or stating that:
\(S_5=\frac{(S_4)^2}{2}\), but \(S_4=\frac{(S_3)^2}{2}\) and so on and so forth all the way to \(S_1\)
OpenStudy (anonymous):
SO:
OpenStudy (anonymous):
ok I am confused what is the final answer they are looking for????