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x/5+7=1
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\[\Large \frac{x}{5}+7=1\]?
yes
Ok well you first have to get x by itself but you have top move the 7 over to the other side, can you do that ?
yes....x/5=-6?
how do i get x by itself?
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x/5 = -6 is correct, now multiply both sides of the equation by 5
ok well, you're diving by 5, so tog et rid of the 5 is you have to do the opposite of division: multiplication, so you multiply by 5
\[\Large (\frac{x}{5}=-6) \times 5\]
\[\Large x= -6 \times 5 \]
so...x=-30?
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yep, now plug it back in the original formula and see if it works
I did....whew! Thanks so much....you're a lifesaver:-)
YW, anytime. =)
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