Someone help?
Find the exact value of the radical expression in simplest form. \[\sqrt{144}-\sqrt{40}-\sqrt{10}\]
\[\sqrt{144}-\sqrt{40}-\sqrt{10}=\sqrt{12*12}-\sqrt{2*2*10}-2\sqrt{10}=12-2\sqrt{10}-2\sqrt{10}\] i think now you can solve.
correction Replace 2sqrt{10} by sqrt{10} at the end.
i cant even see it all
i think only answer is to be written.
does the answer have a 3 in it anywhere
yes
Okay is it \[3\sqrt{10} or 12-3\sqrt{10}\]
\[12-3\sqrt{10}\]
I KNEW IT!!! someone told me that wasnt it
it is simple we have to add the terms with the same sign under radical sign and subtract if they are of different sign.
Can you maybe do a problem for me and write it out
\[5+4\sqrt{3}-3\sqrt{3}-2\sqrt{3}+5\sqrt{3}+3\sqrt{2}-4\sqrt{2}-3\] \[=\left( 5-3 \right)+\left( 4\sqrt{3}+5\sqrt{3} \right)-\left( 3\sqrt{3}+2\sqrt{3} \right)+\left( 3\sqrt{2}-4\sqrt{2} \right)\] \[=2+9\sqrt{3}-5\sqrt{3}-\sqrt{2}=2+4\sqrt{3}-\sqrt{2}\]
have you followed.
yes!!
but like i would give you the problem lol can u do it ?
surely
Nakim simplified: \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18}\] and got \[-10\sqrt{2x}\] for an answer. Part 1: Using complete sentences, explain what Nakim did wrong. Part 2: Show all your work to simplify the expression.
\[3\sqrt{2x}+x \sqrt{2*2*2x}-5\sqrt{3*3*2}\] \[3\sqrt{2x}+2x \sqrt{2x}-5*3\sqrt{2}=\left( 3+2x \right)\sqrt{2x}-15\sqrt{2}\]
it said using complete sentences:)
??
nakim took (3+2x) as (3+2)=5 as he missed x
also he took \[\sqrt{2} as \sqrt{2x}\]
we have to add like terms under the same radical sign he wrote 3+2 in place of 3+2x and then subtracted 15 3+2=5-15=-10
thank you all very much :)
u r welcome
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