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Mathematics 28 Online
OpenStudy (anonymous):

Discrete math, convert expression to NOT, AND, OR. I'm confused about what the question is asking. I wont be able to get help from my professor until tomorrow so maybe someone can help me. I will give a simpler example below.

OpenStudy (anonymous):

(P & Q) is it possible to do the operations above on this statement?

OpenStudy (anonymous):

\(P\land Q\) is already an "and" expression

OpenStudy (anonymous):

Ya that's what I didn't understand about the question. I just think it's worded incorrectly. I have a larger compound statement q -> ( p v r ). He says to convert it to NOT, AND, OR. Any idea now? Thanks!

OpenStudy (anonymous):

yeah in general \(P\to Q \equiv \lnot Q \lor P\)

OpenStudy (anonymous):

Ahh maybe the question is just asking to use the general identities to somehow have NOT AND OR instead of the implication.

OpenStudy (anonymous):

whoa whoa i got that backwards sorry damn

OpenStudy (anonymous):

it should have been \[P\to Q \equiv \lnot P \lor Q\]

OpenStudy (anonymous):

it's ok :).

OpenStudy (anonymous):

so the first step in what you wrote above, (lets see if i can not screw this up) is \[q\to (p\lor v)\equiv \lnot q \lor (p\lor v)\]

OpenStudy (anonymous):

for "or" statements the parenthese are not necessary, so you can simply write \[\lnot q \lor p \lor v\]

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