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Chemistry 13 Online
OpenStudy (anonymous):

Styrene, the building block of polystyrene, is a hydrocarbon, a compound consisting only of C and H. If 0.438 g of styrene is burned in oxygen and produces 1.481 g of CO2 and 0.303 g of H2O, what is the empirical formula of styrene?

OpenStudy (abb0t):

Start by writing down the equation for combstion and styrene.

OpenStudy (abb0t):

C\(_8\)H\(_8\) + O\(_2\) \(\rightarrow\) CO\(_2\) + H\(_2\)O

OpenStudy (abb0t):

Next, find your moles of water and carbon dioxide.

OpenStudy (abb0t):

I'll just wait for you to come back. I dont want to explain something if you may not come back.

OpenStudy (anonymous):

Okay :)

OpenStudy (anonymous):

Hold on

OpenStudy (anonymous):

Now what? o:

OpenStudy (abb0t):

Well, did you find the moles of water and carbon dioxide?

OpenStudy (anonymous):

I got 0.034 mol CO2 & 0.017 mol H20

OpenStudy (abb0t):

Ok, now divide by the higher of the two values, you should get a integer value.

OpenStudy (abb0t):

intuitively, you should see that your ratio is 1:2

OpenStudy (anonymous):

by 0.017?

OpenStudy (anonymous):

Ohhhh

OpenStudy (abb0t):

yes. so you know that your ratio of water and carbon dioxide is 1:2, correct. Are you with me so far.

OpenStudy (anonymous):

Yes (:

OpenStudy (abb0t):

Therefore, you'll notice that you have a 2:2 ratio of hydrogen AND carbon. Remember your formula from above.

OpenStudy (anonymous):

So would I be left with C2O4 & H2O?

OpenStudy (abb0t):

2CO\(_2\) + H\(_2\)O notice you have 2:2 which is the same thing as 1:1 ratio. Therefore, your formla for styrene must be 1:1 But, let's check that.

OpenStudy (abb0t):

2 for Carbon and 2 for hydrogen. YES.

OpenStudy (anonymous):

Ok :) I'm following

OpenStudy (abb0t):

Now, what you do is repeat the same process above with CH and O\(_2\) (on the left side).

OpenStudy (abb0t):

because NOW you know that you have Carbon AND hydrogen.

OpenStudy (abb0t):

So, find the moles of CH and O\(_2\). Can you do that?

OpenStudy (abb0t):

btw, if at any point in time, you're confused as to what I'm doing, please ask.

OpenStudy (anonymous):

You mean by balancing?

OpenStudy (abb0t):

Well, you can do it by balancing, but just to be sure of your answer, you want to do what you did on the other side (on the right). Finding moles by calculation.

OpenStudy (abb0t):

However, you don't know the mass, so just give it a variable, say \(x\). (12.01 + 1.008)\(x\) = approximate molecular mass of styrene.

OpenStudy (anonymous):

Oh okay, I understand now :) The ratio is C to H is 1 so its CH

OpenStudy (abb0t):

Yes.

OpenStudy (abb0t):

that is the \(empirical\) formula, not molecular formula. Do not confuse them.

OpenStudy (anonymous):

Yeah, thank you so much :)

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