How do I calculate the integral?
Thanks for the help! But I actually want to know the process of solving the integral.
Well post your question :)
There are many methods that can be employed ... which makes your question rather vague
\[Let I=\int\limits \sin \left( 4x \right)e ^{-x}dx\] \[=\sin \left( 4x \right)\left( \frac{ e ^{-x} }{-1 } \right)-\int\limits 4\cos \left( 4x \right)\frac{ e ^{-x} }{-1 }dx\] \[=-\sin \left( 4x \right)e ^{-x}+4\left[ \cos \left( 4x \right)\frac{ e ^{-x} }{-1 }-\int\limits \left( -4\sin \left( 4x \right) \right)\frac{ e ^{-x} }{-1 } \right]dx\] \[or I=\left( -\sin \left( 4x \right)-4\cos \left( 4x \right)e ^{-x}-16 I \right)\] \[17 I=-\left( \sin \left( 4x \right) +4 \cos \left( 4x \right)\right)e ^{-x}\] calculate I
integrate twice by parts
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